Current sensitivity of a moving coil galvanometer is 5 div/mA and its voltage sensitivity (angular deflection per unit voltage applied) is 20 div/V. The resistance of the galvanometer is
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a
40 Ω
b
25 Ω
c
250 Ω
d
500 Ω
answer is C.
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Detailed Solution
Let N=number of turns in galvanometer A=Area, B= magnetic fieldk=the restoring torque per unit twist. Current sensitivity, IS=NBAk Voltage sensitivity, VS=NBAkRGSo, resistance of galvanometerRG=ISVS=5×120×10-3=500020=250Ω