Questions
The current through a 4.6 H inductor is shown in the following graph. The induced emf during the time interval t= 5 milli-sec to 6 milli-sec will be
detailed solution
Correct option is C
Rate of decay of current between t = 5 ms to 6 ms=didt=−( Slope of the line BC)=−51×10−3=−5×103A/sHence induced emfε=−Ldidt=−4.6×−5×103=23×103VTalk to our academic expert!
Similar Questions
Two different coils have self-inductance mH, . The current in one coil is increased at a constant rate. The current in the second coil is also increased at the same rate. At a certain instant of time, the power given to the two coils is the same. At that time the current, the induced voltage and the energy stored in the first coil are and respectively. Corresponding values for the second coil at the same instant are and respectively. Then
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