First slide

Inductance

Question

The current through a 4.6 H inductor is shown in the following graph. The induced emf during the time interval t= 5 milli-sec to 6 milli-sec will be

Moderate

A

$10^{3} V$
B

$- 23 \times 10^{3} V$
C

$23 \times 10^{3} V$
D

$z e r o$

Solution

Rate of decay of current between t = 5 ms to 6 ms
$\begin{array}{l} = \frac{d i}{d t} = - (Slope of the line B C) \\ = - (\frac{5}{1 \times 10^{- 3}}) = - 5 \times 10^{3} A / s \end{array}$
Hence induced emf
$ε = - L \frac{d i}{d t} = - 4.6 \times (- 5 \times 10^{3}) = 23 \times 10^{3} V$

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