Q.

The current through 10 Ω resistor in the given part of an electrical circuit, will be

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a

4355A

b

56677A

c

8277A

d

None of these

answer is C.

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Detailed Solution

Let potential of junction is V V−1810+V−28+V−84+V−46=0 V10+V8+V4+V6=1810+28+84+46 (12+15+30+20)V=(18×12+2×15+240+80)77V=566 V=56677  Hence current in 10Ω,I=18−5667710=8277A
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