Current through wire XY of circuit shown is
1 A
4 A
2 A
3 A
−i1 + 0 × ixy +3i2=0 or i1=3i2 ….(i)
Also, −2i1 − ixy + 4i2 + ixy=0
or 2i1 −4 i2 = 6ixy ….(ii)
Also, VAB −1 × i1 −2i1 − ixy=0 ⇒50=i1 +2i1 − ixy=3i1 − 2ixy ….(iii)
Solving (i), (ii) and (iii), ixy = 2A