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Q.

The current and voltage function in an AC circuit areI = 100 sin ⁡100t mAV=100sin⁡100t+π3 volt the power dissipated in the circuit is

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a

10 W

b

2.5 W

c

5 W

d

5 kW

answer is B.

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Detailed Solution

P=VrmsIrmscosϕ and cosϕ=cosπ3=12=1002×1002×10−3×12=2.5W
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