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Q.

The current -voltage relation of diode is given by I = (e1000VT-1)mA, where the applied voltage V is in volts and the temperature T is in degree kelvin. If a student makes an error measuring ±0.01 V while measuring the current of 5 mA at 300 K, what will be the error in the value of current in mA?

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a

0.5 mA

b

0.05 mA

c

0.2 mA

d

0.02 mA

answer is C.

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Detailed Solution

Given 5 = e1000VT- 1⇒  e1000VT = 6-----(i)Again, I = e1000VT-1dIdV = e1000TV 1000Tdl = 1000Te1000TVdVUsing (i) ∆I = 1000T×6×0.01 = 60 T = 60300  = 0.2 mA
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