First slide

Force on a current carrying wire placed in a magnetic field

Question

Currents of 10A, 2A are passed through two parallel wires A and B respectively in opposite directions. If the wire A is infinitely long and the length of the wire B is 2 meter, the force on the conductor B, which is situated at 10 cm distance from A will be

Easy

A

$8 \times 10^{- 5} n e w t o n$
B

$5 \times 10^{- 5} n e w t o n$
C

$8 π \times 10^{- 7} n e w t o n$
D

$4 π \times 10^{- 7} n e w t o n$

Solution

$F = \frac{μ_{o} i_{1} i_{2}}{2 π d} l = \frac{2 \times 10^{- 7} \times 10 \times 2}{0.1} \times 2 = 8 \times 10^{- 5} N$

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