A cyclist is moving with a speed of 6 ms–1. As he approaches a circular turn on the road of radius 120 m, he applies brakes and reduces his speed at a constant rate of 0.4 ms–2. The magnitude of the net acceleration of the cyclist on the circular turn just after brakes is

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0.5 ms–2

1.0 ms–2

2.0 ms–2

4.0 ms–2

answer is A.

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Detailed Solution

at=0.4m/s2ac=Fmac=mv2mrac=v2r⇒62120⇒0.3m/s2anet =ac2+at2=(0.3)2+(0.4)2=0.5

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