A cyclist riding the bicycle at a speed of 143ms−1 takes a turn around a circular road of radius 203m without skidding. Given g= 9.8  m/s2, what is his inclination to the vertical.

According to question, speed of bicycle, v=143ms−1Radius of circular road,r=203m and g=9.8ms−2. Let the inclination of bicycle with normal be θ. For no slip conditionθ=tan−1⁡y2rg=tan−1⁡(143)2203×9.8=tan−1⁡(3)=60∘