A cyclist is riding with a speed of $$27$$ km $$h-1$$. As he approaches a circular turn on the road of radius $$80$$ m, he applies brakes and reduces his speed at the constant rate of $$0.50$$ $$ms-1$$ every second. The net acceleration of the cyclist on the circular turn is

Question

A cyclist is riding with a speed of $$27$$ km $$h-1$$. As he approaches a circular turn on the road of radius $$80$$ m, he applies brakes and reduces his speed at the constant rate of $$0.50$$ $$ms-1$$ every second. The net acceleration of the cyclist on the circular turn is

Infinity Learn · Accepted Answer

Here, v $$=$$ $$27$$ km $$h-1$$ $$=$$ $$27$$ ×$$518ms-1$$   v $$=$$ $$152$$ $$=$$ $$7.5$$ $$ms-1$$  r $$=$$ $$80$$ mCentripetal acceleration, ac $$=$$ $$v2rac$$ $$=$$ $$(7.5$$ $$ms-1)280$$ m $$=$$ $$0.7$$ $$ms-2Tangential$$ acceleration, at $$=$$ $$0.5$$ $$ms-2Magnitude$$ of the net acceleration isa $$=$$ $$(ac)2+(at)2$$ $$=$$ $$(0.7)2+(0.5)2$$ $$=$$ $$0.86$$ $$ms-2$$

A cyclist is riding with a speed of 27 km $h^{- 1}$ . As he approaches a circular turn on the road of radius 80 m, he applies brakes and reduces his speed at the constant rate of 0.50 ${ms}^{- 1}$ every second. The net acceleration of the cyclist on the circular turn is

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A cyclist is riding with a speed of 27 km h-1. As he approaches a circular turn on the road of radius 80 m, he applies brakes and reduces his speed at the constant rate of 0.50 ms-1 every second. The net acceleration of the cyclist on the circular turn is

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Ready to Test Your Skills?

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A cyclist is riding with a speed of 27 km $h^{- 1}$ . As he approaches a circular turn on the road of radius 80 m, he applies brakes and reduces his speed at the constant rate of 0.50 ${ms}^{- 1}$ every second. The net acceleration of the cyclist on the circular turn is