First slide

The two types of acceleration

Question

A cyclist is riding with a speed of 27kmh^–1. As he approaches a circular turn on the road of radius 80m, he applies brakes and reduces his speed at the constant rate of 0.50ms^–1 every second. The net acceleration of the cyclist on the circular turn is

Moderate

A

0.68 ms^–2
B

0.86 ms^–2
C

0.56 ms^–2
D

0.76 ms^–2

Solution

V= 27 kmph = $\frac {15}{2}m/s$ ; r = 80m
${a_C} = \frac{{{V^2}}}{r} = \frac{{15}}{2} \times \frac{{15}}{2} \times \frac{1}{{80}}$
Centripetal acceleration a_c = 0.703m/sec²
Tangential acceleration (ac) = 0.5m/sec²

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