Questions
The cyclotron frequency of an electron moving in a magnetic field of 1 T is approximately
detailed solution
Correct option is D
Cyclotron frequency, v=Bq2πm⇒ v= 1 × 1.6 × 10−192 × 3.14 ×9.1 ×10−31 = 2.79 × 1010 Hz= 27.9 × 109 Hz ≅ 28 GHzTalk to our academic expert!
Similar Questions
A proton is accelerating in a cyclotron having external magnetic field of 0.7 T. If the radii of its dees is 1.8 m, then its maximum kinetic energy (in MeV) is (approximately)
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