A cylinder containing water stands on a table of heightH . A small hole is punched in the side of cylinder at its horizontal distance R from the table. Then, the depth of water in the cylinder is:
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a
H
b
R
c
RH
d
R2/4H
answer is D.
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Detailed Solution
Let h be the height of liquid surface in the vessel. The velocity of efflux is given by veff.=(2gh) If H be the height of table, thenH=12gt2 or t=(2H/g) ∴ R=veff.×t=2gh2H/g R2=4hH or h=R24H
A cylinder containing water stands on a table of heightH . A small hole is punched in the side of cylinder at its horizontal distance R from the table. Then, the depth of water in the cylinder is: