Question

A cylinder contains a gas at temperature of 27⁰C and a pressure 1MPa. If the temperature of the gas is lowered to -23⁰C, the change in pressure is

Easy

Solution

$\frac{P_{1}}{P_{2}} = \frac{T_{1}}{T_{2}}; \frac{P_{2}}{P_{1}} = \frac{T_{2}}{T_{1}} \frac{P_{2} - P_{1}}{P_{1}} = \frac{T_{2} - T_{1}}{T_{1}} = \frac{50}{300} = \frac{1}{6} P_{2} - P_{1} = \frac{1}{6} M P a$

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