First slide

Moment of intertia

Question

A cylinder having mass = 200 g, length = 6 cm, inner radius = 5cm and outer radius = 9 cm. Find moment of inertia about axis of symmetry.

Easy

A

4.02x 10^-4 kg/m²
B

3.03 x 10^-3 kg/m²
C

2.02x 10^-2 kg/m²
D

1.06x 10^-3 kg/m²

Solution

$I = \frac{m (R_{1}^{2} + R_{2}^{2})}{2} = 1 .06 \times 10^{- 3} kg / m^{2}$

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