A cylinder of mass 1kg is given heat of 24000 J at atmospheric pressure. If initially temperature of cylinder is 20°C, then work done by the cylinder will be (Given that Specific heat of cylinder = 400 J kg–1, Coefficient of volume expansion = 9 x 10–5 °C–1, Atmospheric pressure = 105 N/m2 and density of cylinder 9000 kg/m3)

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0.02 J

0.06 J

0.08 J

0.1 J

answer is B.

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Detailed Solution

ΔQ=mcΔT⇒ΔT=24000J1kg×400J/kg∘C=60∘C ⇒TFinal =80∘C Hence W=PatmΔV=PatmV0γΔT =105N/m219×103m39×10−5/∘C60∘C=0.06J

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