First slide

Heat given

Question

A cylinder of mass 1kg is given heat of 24000 J at atmospheric pressure. If initially temperature of cylinder is 20°C, then work done by the cylinder will be (Given that Specific heat of cylinder = 400 J kg^–1, Coefficient of volume expansion = 9 x 10^–5 °C^–1, Atmospheric pressure = 10⁵ N/m² and density of cylinder 9000 kg/m³)

Moderate

A

0.02 J
B

0.06 J
C

0.08 J
D

0.1 J

Solution

$ΔQ = mcΔT \Rightarrow ΔT = \frac{24000 J}{1 kg \times (400 J / {kg}^{\circ} C)} = 60^{\circ} C \Rightarrow T_{Final} = 80^{\circ} C Hence W = P_{atm} ΔV = P_{atm} V_{0} γΔT = (10^{5} N / m^{2}) (\frac{1}{9 \times 10^{3}} m^{3}) (9 \times 10^{- 5} /^{\circ} C) (60^{\circ} C) = 0 .06 J$

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