First slide
Heat given

A cylinder of mass 1kg is given heat of 24000 J at atmospheric pressure. If initially temperature of cylinder is 20°C, then work done by the cylinder will be (Given that Specific heat of cylinder = 400 J kg–1, Coefficient of volume expansion = 9 x 10–5 °C–1, Atmospheric pressure = 105 N/m2 and density of cylinder 9000 kg/m3)


ΔQ=mcΔTΔT=24000J1kg×400J/kgC=60C TFinal =80C  Hence W=PatmΔV=PatmV0γΔT =105N/m219×103m39×105/C60C=0.06J

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