A cylinder of mass $$1kg$$ is given heat of $$24000$$ J at atmospheric pressure. If initially temperature of cylinder is $$20$$°C, then work done by the cylinder will be (Given$$ that Specific heat of cylinder $$=$$ $$400$$ J kg–$$1$$, Coefficient of volume expansion $$=$$ $$9$$ x $$10$$–$$5$$ °C–$$1$$, Atmospheric pressure $$=$$ $$105$$ $$N/m2$$ and density of cylinder $$9000$$ $$kg/m3)

Question

Infinity Learn · Accepted Answer

Δ$$Q=mc$$ΔT⇒Δ$$T=24000J1kg$$×$$400J/kg$$∘$$C=60$$∘C ⇒TFinal $$=80$$∘C  Hence $$W=Patm$$Δ$$V=PatmV0$$γΔT $$=105N/m219$$×$$103m39$$×$$10$$−$$5/$$∘$$C60$$∘$$C=0.06J$$

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