A cylinder of mass 4 m and a block of mass m is placed on an inclined plane as shown in the figure. The linear acceleration of cylinder is

The velocity of the block and the velocity of the top point of the cylinder same i.e., doble  the velocity of center of mass,  from conservation of energy.mgh=12 mυ2+124mυ22 1+k2R2mgh=12 mυ2+124mυ22 1+12=12 mυ2+12mυ232=12 mυ21+32mgh=12 mυ2524gh5=υ2           υ2=2ah2a=4g5a=2g5=4m/s2