A cylinder of radius R and length L is placed in a uniform electric field E parallel to the cylinder axis. The total flux for the surface of the cylinder is given by

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2πR2E

πR2/E

(πR2−πR)/E

Zero

answer is D.

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Detailed Solution

Flux through surface A ϕA=E×πR2 and ϕB=−E×πR2Flux through curved surface C=∫E→⋅d→s=∫Edscos⁡90∘=0∴Total flux through cylinder =ϕA+ϕB+ϕC=0