A cylinder of radius R and length L is placed in a uniform electric field E parallel to the cylinder axis. The total flux for the surface of the cylinder is given by:
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a
2πR2E
b
πR2/E
c
πR2−πR/E
d
Zero
answer is D.
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Detailed Solution
Flux through surface A ϕA=E×πR2 and ϕB=−E×πR2Flux through curved surfaceϕc=∫E→⋅d→s=∫Edscos90∘=0Total flux through cylinder =ϕA+ϕB+ϕC=0