A cylinder, released from the top of an inclined plane, rolls without sliding and reaches the bottom with speed vr. Another identical cylinder, released from the top of the same inclined plane, slides without rolling and reaches the bottom with speed vs. Then

When the cylinder rolls without sliding, the acceleration down the plane is ar=23gsin⁡θ ∵a=gsinθ1+β and β=12When the cylinder slides without rolling, the acceleration isas=gsin⁡θwhere θ is the inclination of the plane.If h is the height of the inclined plane, their speeds on reaching the bottom are given by vr=2arh and vs=2ashSince as>ar, it follows that vs>vr, which is choice (b).