Download the app

Questions  

A cylindrical bar magnet ( radius = 1 cm , length = 10 cm ) has field intensity of 1000 A/m . The magnetic moment  in the bar if permeability of its material is 6.3×104H/m  is ----------

a
15.50Am2
b
15.70Am2
c
18.70Am2
d
20.7Am2

detailed solution

Correct option is B

We know  μ=μ0(1+χ)                                    χ=μμ0−1=6.3×10−44π×10−7−1 ≃ 500Intensity of magnetizationI=χH=500 × 1000=5×105A/m⇒Magnetic moment  (M)=I V                                                 ⇒M=Iπr2L⇒M=5×105×3.14×(10−2)2×(10×10−2)⇒M=15.70Am2

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A paramagnetic substance of susceptibility 3×104 is placed in a magnetic field intensity of 6×104A.m1 . Then the intensity of magnetization in the units of Am1 is__  


phone icon
whats app icon