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Questions  

A cylindrical drum, pushed along by a board rolls forward on the ground. There is no slipping at any contact. The distance moved by the man who is pushing the board, when axis of the cylinder covers a distance L will be

a
L
b
2L
c
πL
d
8πL

detailed solution

Correct option is B

Let v0 be the linear speed of the axis of the cylinder and ω be its angular speed about the axis. As it does not slip on the ground hence ω = v0R. Where R is the radius of the cylinder.  Speed of the topmost point is v = v0+ωR = 2v0Since time taken by the axis to move a distance L is equal to t = Lv0.In the same interval of time distance moved by the topmost point is S = 2v0×Lv0 = 2L

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Similar Questions

I. Speed of any point on rigid body executing rolling motion can be calculated by the expression ν=rω
where r is the distance of point from instantaneous centre of rotation.
II. Rolling motion of rigid body can be considered as a pure rotation about instantaneous centre of rotation.
Which of the above statement{s} is/are correct? 


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