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A cylindrical rod magnet has a length of 5 cm and a diameter of 1 cm. It has a uniform magnetization of 5.30 x 103A/m. What its magnetic dipole moment?

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a

1 x 10-2 J/T

b

2.08 x 10-2 J/T

c

3.08 x 10-2 J/T

d

1.52 x 10-2 J/T

answer is B.

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Detailed Solution

Relation for dipole moment is, M = I x V. Volume of the cylinder V=πr2L, where r is the radius and L is the length of the cylinder. Then dipole moment, M=Iπr2L=5.30 x 103 x 227 x 0.5 x 10-225 x 10-2=2.08 x 10-2 J/T

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A cylindrical rod magnet has a length of 5 cm and a diameter of 1 cm. It has a uniform magnetization of 5.30 x 103A/m. What its magnetic dipole moment?