First slide

Fluid dynamics

Question

A cylindrical tank of base area A has a small hole of area ‘a’ at its bottom. At the time t = 0, a tap starts to supply water into the tank at the rate of αm³/sec. The maximum level of water in the tank is

Easy

A

$\large \frac {\alpha^2}{2ga^2}$
B

$\large \frac {\alpha}{2g}$
C

$\large \frac {\alpha}{2ag}$
D

$\large \frac {2ga} {\alpha}$

Solution

Velocity of efflux, $\large V=\sqrt {2gh_{max}}$
$\large \therefore \alpha=aV=a\sqrt {2gh_{max}}$
$\large \alpha^2=a^2 \times 2gH_{max}\Rightarrow H_{max}=\frac {\alpha^2}{2a^2g}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App