A cylindrical tank is filled with water to a level of 3 m. a hole is opened at a height of 52.5 cm from bottom. The ratio of the area of the hole to that of cross-sectional area of cylinder is 0.1. find the square of velocity with which water is coming out: (g=10 m/s2)

Let A  be the area of cross-section of tank. Let a  be the area of hole, v  be the velocity of efflux and V  be the speed with which level decreases.According to equation of continuityAV=av  or V=avA  …(1) According to Bernoulli’s theoremP0+Hρg+12ρ[avA]2=P0+12ρv2 ∴  v2=2Hg1−(aA)2 =2×(3−0.525)×101−(0.1)2 =50 m2/sec2