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A cylindrical, tank is filled with water to a level of 3 m. A hole is opened at a height of 52.5 cm from bottom. The ratio of the area of the hole to that of cross-sectional area of the cylinder is 0.1. Find the square of the velocity with which water is coming out: (g=10 m/sec2)

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a

50 m2/sec2

b

40 m2/sec2

c

60 m2/sec2

d

25 m2/sec2

answer is A.

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Detailed Solution

ρ0+ Hρg + 12 ρaveA2=ρ0 + 12ρv2 e∴v2 e=2Hg1−aA2==23-0.525101−0.12=50m2/s2

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A cylindrical, tank is filled with water to a level of 3 m. A hole is opened at a height of 52.5 cm from bottom. The ratio of the area of the hole to that of cross-sectional area of the cylinder is 0.1. Find the square of the velocity with which water is coming out: (g=10 m/sec2)