A cylindrical tube, open at both ends, has a fundamental frequency f0 in air. The tube is dipped vertically into water such that half of its length is inside water. The fundamental frequency of the air column now is
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a
3f0/4
b
f0
c
f0/2
d
2f0
answer is B.
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Detailed Solution
nopen=v2lopennclosed=v4lclosed=v4lopen/2=v2lopenAs lclosed=lopen2, i.e. frequency remains unchanged.