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A cylindrical tube, open at both ends, has a fundamental frequency f0 in air. The tube is dipped vertically into water such that half of its length is inside water. The fundamental frequency of the air column now is 

a
3f0/4
b
f0
c
f0/2
d
2f0

detailed solution

Correct option is B

nopen=v2lopennclosed=v4lclosed=v4lopen/2=v2lopenAs lclosed=lopen2, i.e. frequency remains unchanged.

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Similar Questions

A tube of certain diameter and of length 48 cm is open at both ends. Its fundamental frequency of resonance is found to be 320 Hz. The velocity of sound in air is 320 m/s. One end of the tube is now closed, considering the effect of end correction, calculate the lowest frequency of resonance for the tube (in Hz). 


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