The cylindrical tube of a spray pump has a radius,H, one end of which has n fine holes, each of radius r. If the speed of flow of the liquid in the tube is y, the speed of ejection of the liquid through the hole is

Cross-sectional area of the tube =A=πR2 speed of flow of liquid in the tube = Vcross-sectional area of each hole =πr2cross-sectional area of n hole =nπr2kt the speed of ejection of liquid through the hole = vAccording to continuity equation aV=AV nπr2V=πR2V V=VnRr2