A cylindrical tube of uniform cross-sectional area A is fitted with two air tight frictionless pistons.The pistons are connected to each other by a metallic wire. Initially, the pressure of the gas is p0 and temperature is T0, atmospheric pressure is also p0. Now, the temperature of the gas is increased to 2T0, the tension in the wire will be

Volume of the gas V is constant.∴  p ∝T, i.e. pressure will be doubled when temperature is doubled.∴                                   p = 2p0Now, let F be the tension in the wire. Then, equilibrium of anyone piston will give                                       F = (p-p0)A                                          = (2p0-p0)A                                           = p0A