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A cylindrical tube, with its base as shown in the figure, is filled with water. It is moving down with a constant acceleration a along a fixed inclined plane with angle θ=45. P1 and P2 are pressure at points 1 and 2, respectively, located at the base of the tube Let β=P1P2/(ρgd), where ρ is density of water, d is the inner diameter of the tube and g is the acceleration due to gravity. Which of the following statement(s) is(are) correct ?

a
β=0 when a=g/2
b
β>0 when a=g/2
c
β=2−12 when a=g/2
d
β=12 when a=g/2

detailed solution

Correct option is A

P1+ρ(2d)a−ρg2(2d)=P2P1−P2=ρd(−2a+g)β=P1−P2ρgd=−2ag+1 if β=0⇒a=g2 if a=g2 then β=2−12

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