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Q.

A cylindrical uniform rod of mass 0.72 kg and radius 6 cm rests on two parallel rails, that are d = 50 cm apart. The rod carries a current I = 48A (In the direction shown) and rolls along the rails without slipping. If it starts from rest, uniform magnetic field of magnitudes 0.25 T is directedperpendicular to the rod and the rail, then find the friction force(In N) between rod and rails

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answer is 00002.00.

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Detailed Solution

f=F3=idB3⇒48×0.5×0.253=2.00
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A cylindrical uniform rod of mass 0.72 kg and radius 6 cm rests on two parallel rails, that are d = 50 cm apart. The rod carries a current I = 48A (In the direction shown) and rolls along the rails without slipping. If it starts from rest, uniform magnetic field of magnitudes 0.25 T is directedperpendicular to the rod and the rail, then find the friction force(In N) between rod and rails