A cylindrical vessel contains a liquid of density ρ up to a height h . The liquid is closed by a piston of mass m and area of cross-section A . There is a small hole at the bottom of the vessel. The speed v with which the liquid comes out of the hole is:
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a
2gh
b
2(gh+mgρA)
c
2(gh+mgA)
d
2gh+mgA
answer is B.
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Detailed Solution
Applying Bernoulli’s theorem at point 1 and 2, Difference in pressure energy between 1 and 2 = difference in kinetic energy between 1 and 2or ρhg+mgA=12ρv2or v=2gh+2mgρA=2(gh+mgρA)