First slide

Fluid statics

Question

A cylindrical vessel is filled with equal amounts by weight of mercury and water. The overall height of the two layers is 29.2 cm. Specific gravity of mercury is 13 . 6. Then the pressure of the liquids at the bottom of the vessel is

Easy

A

29 .213.6 cm of mercury
B

4 cm of mercury
C

3/2 cm of mercury
D

t5.6 cm of mercury

Solution

If x cm be the height of mercur5r column, then the height of water column be 13'6 x cm.
$∴ x + 13 \cdot 6 x = 29 \cdot 2 or x = 2 cm$ So, height of mercury column = 2 cm and height of water column=27.2 cm (equivalent to 2 cm of mercury column)
pressure at bottom = [2 cm + 2 cm) = 4cm of mercury.

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