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Q.

A cylindrical wire of radius 0.5 mm and conductivity 5×107 S/m  is subjected to an electric field of 10 mV/m. The expected value of current in the wire will be x3π   mA. The value of ‘x’ is ……….

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answer is 5.

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Detailed Solution

Ohm's Law , J=σE⇒iA=σE⇒i=σEA⇒i=5×107×10×10−3×π×25×10−8⇒i=125π×10−3⇒i=125πmASo, x=5
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