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At 120 dB sound level intensity of sound is 1W/m2. Now at sound level 121 dB intensity will be :

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a

1.1W/m2

b

1.26W/m2

c

2W/m2

d

11W/m2

answer is B.

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Detailed Solution

120=10log⁡I110−12… (i) I1=1W/m2121=10log⁡I110−12… (ii) By (ii) − (i) 121−120=10log⁡I2/I1I2=I1101/10I2=1.25W/m2

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