First slide

Matter waves (DC Broglie waves)

Question

The de Broglie wavelength of the electron in the first Bohr orbit of the hydrogen atom is

Easy

A

equal to the diameter of the first orbit
B

equal to the circumference of the first orbit
C

equal to half the circumference of the first orbit
D

independent of the size of the first orbit

Solution

$λ = \frac{h}{p} = \frac{h}{mv} and mvr = \frac{h}{2 π}$ solving we get $λ = 2 πr$

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