The de Broglie wavelength of the electron in the first Bohr orbit of the hydrogen atom is

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equal to the diameter of the first orbit

equal to the circumference of the first orbit

equal to half the circumference of the first orbit

independent of the size of the first orbit

answer is B.

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Detailed Solution

λ=hp=hmv and mvr=h2π solving we get λ=2πr

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