Questions

The de Broglie wavelength of the electron in the first Bohr orbit of the hydrogen atom is

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a

equal to the diameter of the first orbit

b

equal to the circumference of the first orbit

c

equal to half the circumference of the first orbit

d

independent of the size of the first orbit

detailed solution

Correct option is B

λ=hp=hmv and mvr=h2π solving we get λ=2πr

Similar Questions

An electron is orbiting in 4^{th} energy state in a hydrogen atom. The de-Broglie wavelength associated with this electron is nearly equal to

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