The de Broglie wavelength of the electron in the first Bohr orbit of the hydrogen atom is

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

equal to the diameter of the first orbit

equal to the circumference of the first orbit

equal to half the circumference of the first orbit

independent of the size of the first orbit

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

λ=hp=hmv and mvr=h2π solving we get λ=2πr

Watch 3-min video & get full concept clarity