Q.
The de Broglie wavelength of the electron in the first Bohr orbit of the hydrogen atom is
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a
equal to the diameter of the first orbit
b
equal to the circumference of the first orbit
c
equal to half the circumference of the first orbit
d
independent of the size of the first orbit
answer is B.
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Detailed Solution
λ=hp=hmv and mvr=h2π solving we get λ=2πr
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