First slide

Matter waves (DC Broglie waves)

Question

The de Broglie wavelength of an electron moving with kinetic energy of 144 eV is nearly

Moderate

A

$102 \times 10^{- 2} nm$
B

$102 \times 10^{- 3} nm$
C

$102 \times 10^{- 4} nm$
D

$102 \times 10^{- 5} nm$

Solution

de Broglie wavelength of electron,
$\begin{array}{l} λ = \frac{12.27}{\sqrt{k (in eV)}} Å \\ = \frac{12.27}{\sqrt{144}} = \frac{12.27}{12} = 1.02 Å \\ = 102 \times 10^{- 3} nm \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App