First slide

Matter waves (DC Broglie waves)

Question

The de Broglie wavelength of an electron and the wavelength of a photon are the same. The ratio between the energy of that photon and the momentum of that electron is (c is velocity of light, h is Planck's constant)

Moderate

A

h
B

c
C

1/h
D

1/c

Solution

According to question, we have De Broglie wavelength of electron = Wavelength of photon
$\frac{h}{p_{electron}} = \frac{h c}{E_{photon}}$ , where p is the momentum of electron, c is speed of light, E is energy of photon and h is Planck's constant.
$\frac{E_{photon}}{p_{electron}} = \frac{h c}{h} = c$

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