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Q.

de Broglie wavelength of neutron having kinetic energy of 5 MeV is λ. Then what will be the de Broglie wavelength of α−particle having kinetic energy of 20 MeV?

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a

λ4

b

λ2

c

λ

d

2λ

answer is A.

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Detailed Solution

p22m=E⇒p=2mE⇒λ=hp=h2mE∴ λαλn=mnmα.EnEα⇒λαλ=m4m.520=14⇒λα=λ4

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de Broglie wavelength of neutron having kinetic energy of 5 MeV is λ. Then what will be the de Broglie wavelength of α−particle having kinetic energy of 20 MeV?