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Q.

The de-Broglie wavelength of an electron having 80 eV of energy is nearly(1 ev =1.6×10-19 J, Mass of electron =9×10-31kg Plank's constant=6.6×10-34 J-sec)

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a

140 Ao

b

0.14 Ao

c

14 Ao

d

1.4 Ao

answer is D.

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Detailed Solution

λ=h2mE =6.6×10-342×9×10-31×80×1.6×10-19=1.4Ao

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