Q.

The de-broglie wavelength of an electron and wavelength of a photon are the same. The ratio between the energy of the photon and the momentum of the electron is

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a

h

b

c

c

1h

d

1c

answer is B.

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Detailed Solution

λe=λphEph=hcλph,Pe=hλeEph Pe=hcλphhλe=c
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