First slide

Acceeleration due to gravity on surface of planet

Question

The density of earth in terms of acceleration due to gravity (g), radius of earth (R) and universal gravitational constant (G) is :

Moderate

A

$\frac{4 πRG}{3 g}$
B

$\frac{3 πRG}{4 g}$
C

$\frac{4 g}{3 πRG}$
D

$\frac{3 g}{4 πRG}$

Solution

$g = \frac{GM}{R^{2}} = \frac{4}{3} πGρR \Rightarrow ρ = \frac{3 g}{4 πGR}$

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