Q.

The density of earth in terms of acceleration due to gravity (g), radius of earth (R) and universal gravitational constant (G) is :

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a

4πRG3g

b

3πRG4g

c

4g3πRG

d

3g4πRG

answer is D.

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Detailed Solution

g=GMR2=43πGρR⇒ρ=3g4πGR
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The density of earth in terms of acceleration due to gravity (g), radius of earth (R) and universal gravitational constant (G) is :