The density of a metal at normal pressure is ρ. Its density when it is subjected to an excess pressure P is ρ'. If B is the bulk modulus of the metal, then the ratio ρ'/ρ is
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a
1+P/B
b
1+B/P
c
1(1−B/P)
d
1(1−P/B)
answer is D.
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Detailed Solution
Magnitude of bulk modulus,B=PdV/V or dV=PVB∴ ρ′=MV−dV=MV−(PV/B)=MV(1−P/B)=ρ(1−P/B) ∵ρ=MV∴ ρ′ρ=1(1−P/B)
The density of a metal at normal pressure is ρ. Its density when it is subjected to an excess pressure P is ρ'. If B is the bulk modulus of the metal, then the ratio ρ'/ρ is