Q.
The density of a polyatomic gas in standard conditions is 0.795 kgm-3. The specific heat of the gas at constant volume is
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a
930JKg-1 K-1
b
1400JKg-1 K-1
c
1120JKg-1 K-1
d
1600JKg-1 K-1
answer is B.
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Detailed Solution
standard pressure P=1.013×105 pascal; temperature T=273K; density=0.795kgm-3 PV=mrT ;here r=specific gas constant; m=mass of gas;V=volume of gas ⇒P=(m/V)rT ⇒P=ρrT ; here ρ =density of gas ⇒r=P/ρT ⇒r=1.013×1050.795×273=466.7 ∴ we know CV=rγ-1=specific heat of gas at constant volume;specific heat ratio γ=43;substitute legibly CV=466.743-1=1400JKg-1 K-1
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