Q.

The density of a polyatomic gas in standard conditions is 0.795 kgm-3. The specific heat of the gas at constant volume is

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a

930J−kg−1K−1

b

1400J−kg−1K−1

c

1120J−kg−1K−1

d

1600J−kg−1K−1

answer is B.

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Detailed Solution

Ideal gas equation for m grams of gas is                     PV = mrT                (where r = specific gas constant)or   P=mVrT=ρrT⇒ r=PρT=1.013×1050.795×273=466.7Specific heat at constant volumecv=rγi-1=466.743-1=1400J/kg−K                                         (γ=4/3 for polyatomic gas )
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