Q.
The density of a polyatomic gas in standard conditions is 0.795 kgm-3. The specific heat of the gas at constant volume is
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a
930J−kg−1K−1
b
1400J−kg−1K−1
c
1120J−kg−1K−1
d
1600J−kg−1K−1
answer is B.
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Detailed Solution
Ideal gas equation for m grams of gas is PV = mrT (where r = specific gas constant)or P=mVrT=ρrT⇒ r=PρT=1.013×1050.795×273=466.7Specific heat at constant volumecv=rγi-1=466.743-1=1400J/kg−K (γ=4/3 for polyatomic gas )
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