First slide

Instantaneous acceleration

Question

Depict the shown v-x graph in a-x graph

Moderate

A
B
C
D

Solution

$From the v - x graph slope of the graph is (\frac{dv}{dx}) = - (\frac{v_{0}}{x_{0}}) = - k and velocity changes with distance as v = - kx + v_{0} a = v (\frac{dv}{dx}) = (- kx + v_{0}) (- k) a = k^{2} x - {kv}_{0} having a positive slope but negative y intercept hence option 1 is correct$

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