First slide

P-N junction

Question

The depletion layer in silicon diode is 1 µm wide and the knee potential is 0.6 V, then the electric field in the depletion layer will be

Moderate

A

Zero
B

0.6 V/m
C

$6 x 10^{4} V / m$
D

$6 x 10^{5} V / m$

Solution

By using $E = \frac{V}{d} = \frac{0.6}{10^{- 6}} = 6 \times 10^{5} V / m$

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