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Q.

The depth d at which the value of acceleration due to gravity becomes 1n times the value at the surface, is [R = radius of the earth]

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a

Rn

b

R n−1n

c

Rn2

d

R nn+1

answer is B.

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Detailed Solution

g′=g1−dR⇒gn=g1−dR⇒d=n−1nR
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The depth d at which the value of acceleration due to gravity becomes 1n times the value at the surface, is [R = radius of the earth]