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Questions  

The depth d at which the value of acceleration due to gravity becomes 1n times the value at the surface, is [R =radius of the earth]

a
Rn
b
R(n-1n)
c
Rn2
d
R(nn+1)

detailed solution

Correct option is B

g' = g(1-dR)  ⇒gn = g(1-dR)⇒dR = 1-1n ⇒d = (n-1n)R

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