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Q.

The depth d at which the value of acceleration due to gravity becomes 1n times the value at the surface, is [R =radius of the earth]

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a

Rn

b

R(n-1n)

c

Rn2

d

R(nn+1)

answer is B.

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Detailed Solution

g' = g(1-dR)  ⇒gn = g(1-dR)⇒dR = 1-1n ⇒d = (n-1n)R
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