First slide

Variation of g

Question

The depth at which the effective value of acceleration due to gravity is $\frac{g}{4}$ is (R = radius of the earth)

Easy

A

R
B

$\frac{3 R}{4}$
C

$\frac{R}{2}$
D

$\frac{R}{4}$

Solution

$g^{'} = g (1 - \frac{d}{R}) \Rightarrow \frac{g}{4} = g (1 - \frac{d}{R}) \Rightarrow d = \frac{3 R}{4}$

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